document.write( "Question 997142: a 200 km trip was made by canoeing at 5km/h and cycling at 30 km/h. if the total time of the trip was 15 hours, find the distance traveled by each \n" ); document.write( "
Algebra.Com's Answer #615412 by MathTherapy(10551)\"\" \"About 
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\n" ); document.write( "a 200 km trip was made by canoeing at 5km/h and cycling at 30 km/h. if the total time of the trip was 15 hours, find the distance traveled by each
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Let distance canoeing be D
\n" ); document.write( "Then distance cycling = 200 – D
\n" ); document.write( "Time spent canoeing: \"D%2F5\", and time spent cycling was: \"%28200+-+D%29%2F30\"
\n" ); document.write( "With total time being 15 hours, we get: \"D%2F5+%2B+%28200+-+D%29%2F30+=+15\"
\n" ); document.write( "6D + 200 – D = 450 --------- Multiplying by LCD, 30
\n" ); document.write( "6D – D = 450 – 200
\n" ); document.write( "5D = 250
\n" ); document.write( "D, or distance canoeing = \"250%2F5\", or \"highlight_green%2850%29\" km
\n" ); document.write( "Distance cycling: 200 – 50, or \"highlight_green%28150%29\" km \n" ); document.write( "
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