document.write( "Question 997209: Gary can finish an engineering work in 8 hours. Clint can finish the same work in 6 hours. After 2 hours working together, Gary left for lunch and Clint finished the job. How long does it take Clint to finish the job? \n" ); document.write( "

Algebra.Com's Answer #615408 by josgarithmetic(39621) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Engineers     rate             time        work\r\n" );
document.write( "GARY          1/8              \r\n" );
document.write( "CLINT         1/6               t          (1/6)t\r\n" );
document.write( "BOTH          (1/8+1/6)         2          (1/8+1/6)*2\r\n" );
document.write( "Total                                       1\r\n" );
document.write( "

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\n" ); document.write( "\n" ); document.write( "RT=W, basic uniform rate relationship to do work;
\n" ); document.write( "This example uses W=1, for ONE WHOLE WORK or JOB.\r
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\n" ); document.write( "\n" ); document.write( "Most logical next step is form equation $\"t%2F6%2B2%2F8%2B2%2F6=1\"$
\n" ); document.write( " $\"t%2F6%2B1%2F4%2B1%2F3=1\"$ , LCD is 12,
\n" ); document.write( " $\"12%28t%2F6%2B1%2F4%2B1%2F3%29=12\"$
\n" ); document.write( " $\"2t%2B3%2B4=12\"$
\n" ); document.write( " $\"2t=12-7\"$
\n" ); document.write( " $\"2t=5\"$
\n" ); document.write( " $\"highlight%28t=2%261%2F2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "~~Find t~~. \n" ); document.write( "

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