document.write( "Question 997131: Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #615358 by ikleyn(52788)\"\" \"About 
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Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?
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\n" ); document.write( "\n" ); document.write( "\"%280.1%2Ax+%2B0.3%2A%2850-x%29%29%2F50\" = 0.18.\r
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\n" ); document.write( "\n" ); document.write( "Numerator is the amount of the soluted sugar, x is a volume of the 10% solution.\r
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\n" ); document.write( "\n" ); document.write( "0.1x + 0.3*(50-x) = 0.18*50,\r
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\n" ); document.write( "\n" ); document.write( "0.1x - 0.3x = 9 - 15,\r
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\n" ); document.write( "\n" ); document.write( "-0.2x = -6,\r
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\n" ); document.write( "\n" ); document.write( "x = \"6%2F0.2\" = 30.\r
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\n" ); document.write( "\n" ); document.write( "Answer. 30 liters of 10% solution and 50-30 = 20 liters of 30% solution.\r
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