document.write( "Question 997122: Please Help again!:
\n" ); document.write( "x=2 to the power of p.
\n" ); document.write( "Y= 2 to the power of q.
\n" ); document.write( "Express in terms x and or/y,
\n" ); document.write( "(i) 2 to the power of p+q
\n" ); document.write( "(ii) two to the power of 2q
\n" ); document.write( "(iii) 2 to the power of p-1.
\n" ); document.write( "This should count as 1 question as its three parts! Thank you very much kind tutors, and have fantastic days!
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Algebra.Com's Answer #615352 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "x=2 to the power of p.
\n" ); document.write( "Y= 2 to the power of q.
\n" ); document.write( "Express in terms x and or/y,
\n" ); document.write( "(i) 2 to the power of p+q
\n" ); document.write( "(ii) two to the power of 2q
\n" ); document.write( "(iii) 2 to the power of p-1.
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\n" ); document.write( "\n" ); document.write( "\"x\" = \"2%5Ep\",     \"y\" = \"2%5Eq\".\r
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\n" ); document.write( "\n" ); document.write( "(I)  \"2%5E%28p%2Bq%29\" = \"2%5Ep\".\"2%5Eq\" = \"x%2Ay\".\r
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\n" ); document.write( "\n" ); document.write( "(ii)  \"2%5E%282q%29\" = \"2%5Eq\"*\"2%5Eq\" = \"y%2Ay\" = \"y%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "(iii)  \"2%5E%28p-1%29\" = \"1%2F2\".\"2%5Ep\" = \"1%2F2\".\"x\" = \"x%2F2\".\r
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