document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997081>Question 997081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve\r<BR>\n" );
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document.write( "Write an absolute value inequality representing all numbers that are at least 2 units from 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615331 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your absolute value inequality will be |x - 2| > 5\r<BR>\n" );
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document.write( "when (x-2) is positive, the inequality becomes (x - 2) > 5.\r<BR>\n" );
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document.write( "add 2 to both sides of thsi inequality to get x > 7.\r<BR>\n" );
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document.write( "when (x-2) is negative, you flip the sign of the expression on the right and you slip the inequality sign to get (x - 2) < - 5.\r<BR>\n" );
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document.write( "add 2 to both sides of this inequality to get x < -3\r<BR>\n" );
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document.write( "your solution would then be that x > 7 and x < -3.\r<BR>\n" );
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document.write( "when x = 8 which is greater than 7, |x-2| > 5 becomes |8-2| > 5 which becomes |6| > 5 which becomes 6 > 5 which is true.\r<BR>\n" );
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document.write( "when x = -4 which is less than -3, |x-2| > 5 becomes |-4-2| > 5 which becomes |-6| > 5 which becomes 6 > 5 which is true.\r<BR>\n" );
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document.write( "the solution is confirmed to be good.\r<BR>\n" );
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