document.write( "Question 997076: ali's father was five times as old as Ali 7 1/2 years ago.After 7 1/2 years father will be twice as old as ALI .what are their present ages?
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document.write( "a,12 1/2,32 1/2 b,5,25 c,12,32 d,5 1/2,25 1/2 \n" );
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Algebra.Com's Answer #615327 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 7.5 years ago\r \n" ); document.write( "\n" ); document.write( "ali -----x \n" ); document.write( "father 5x\r \n" ); document.write( "\n" ); document.write( "after 7.5 years\r \n" ); document.write( "\n" ); document.write( "ali ---x+15 \n" ); document.write( "father 5x+15\r \n" ); document.write( "\n" ); document.write( "2(x+15) =5x+15\r \n" ); document.write( "\n" ); document.write( "2x+30 = 5x+15 \n" ); document.write( "3x =15 \n" ); document.write( "x=5\r \n" ); document.write( "\n" ); document.write( "Ali present age = 5 +7.5 = 12.5 years\r \n" ); document.write( "\n" ); document.write( "father's age =( 5 * 5)+7.5 = 32.5 years \n" ); document.write( " |