document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997006>Question 997006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alex travels twice as far as john, but only one third as fast. John starts at point x at noon on Monday and travels to point z, 300 away, b y 9:00 pm the same day. If alex starts 3 hour later than john, when will alex reach point z.. ( assuming no stops were made<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615286 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance= rate x time (rate is another word for speed)<BR>\n" );
document.write( "For John, we know the distance (300mi) and the time (9hrs) so we need to find the rate: <BR>\n" );
document.write( "We divide both sides of the equation by time:<BR>\n" );
document.write( "Distance/time= rate<BR>\n" );
document.write( "300/9= 33.33 miles per hour is John's speed.<BR>\n" );
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document.write( "Alex travels twice as far at 1/3 the speed, so Alex goes 600 miles at 11.11mph:<BR>\n" );
document.write( "Distance= rate*time Divide both sides by rate<BR>\n" );
document.write( "distance/rate= time<BR>\n" );
document.write( "600/11.11= 54hours; 54/24= 2 days and 6 hours<BR>\n" );
document.write( "Alex starts at 12+3 at 3pm and finishes 2 days later at 9pm </SPAN>\n" );
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