document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996860>Question 996860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> part of the proceeds from a garage sale was 290 worth of $5 and $20 bills, if there were 3 more $5 bills than $20 bills. find the number of each denomination </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615254 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # of $5 bills.<BR>\n" );
document.write( "Let y = # of $20 bills.<BR>\n" );
document.write( "The value equation is<BR>\n" );
document.write( "5x + 20y = 290<BR>\n" );
document.write( "The other equation is<BR>\n" );
document.write( "x = y + 3<BR>\n" );
document.write( "Substituting this into the first equation gives<BR>\n" );
document.write( "5(y + 3) + 20y = 290<BR>\n" );
document.write( "5y + 15 + 20y = 290<BR>\n" );
document.write( "25y = 275<BR>\n" );
document.write( "y = 11<BR>\n" );
document.write( "x = 14 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );