document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996950>Question 996950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sum of present ages of a mother and daughter is 47. After 5 years, mother will be 6 more than 2 times her daughter's age. Find their present ages.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615244 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the mother's age now, x.  The daughter's age is y.<BR>\n" );
document.write( "Thus x + y = 47, and x = 47 - y.<BR>\n" );
document.write( "In five years,<BR>\n" );
document.write( "x + 5 = 6 + 2(y + 5)  or<BR>\n" );
document.write( "x + 5 = 6 + 2y + 10<BR>\n" );
document.write( "x + 5 = 2y + 16<BR>\n" );
document.write( "x = 2y + 11<BR>\n" );
document.write( "Substituting in, we get<BR>\n" );
document.write( "47 - y = 2y + 11<BR>\n" );
document.write( "36 = 3y<BR>\n" );
document.write( "y = 12<BR>\n" );
document.write( "x = 35 </SPAN>\n" );
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