document.write( "Question 996943: the present ratio between the age of father and son is 20:1.\r
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document.write( "After 6 years the ratio will become 5:1.\r
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document.write( "find the present age of father\r
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document.write( "A,18 YEARS B, 24 YEARS C,32 YEARS D,35 YEARS \n" );
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Algebra.Com's Answer #615206 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! x = age of father \n" ); document.write( "y = age of son\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present ratio of father and son = 20:1 \n" ); document.write( "so\r \n" ); document.write( "\n" ); document.write( "(age of father)/(age of son) = 20/1 \n" ); document.write( "x/y = 20/1 \n" ); document.write( "x/y = 20 \n" ); document.write( "x = 20*y ... multiply both sides by y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"after 6 years, the ratio will become 5:1\", so,\r \n" ); document.write( "\n" ); document.write( "(x+6)/(y+6) = 5/1 \n" ); document.write( "(x+6)/(y+6) = 5 \n" ); document.write( "x+6 = 5*(y+6) \n" ); document.write( "20y+6 = 5*(y+6) ... replace x with 20y (see above) \n" ); document.write( "20y+6 = 5y+30 \n" ); document.write( "20y+6 - 5y = 5y+30-5y ... Subtract 5y from both sides. \n" ); document.write( "15y+6 = 30 \n" ); document.write( "15y+6-6 = 30-6 ... Subtract 6 from both sides. \n" ); document.write( "15y = 24 \n" ); document.write( "15y/15 = 24/15 ... Divide both sides by 15. \n" ); document.write( "y = 24/15 \n" ); document.write( "y = 8/5 \n" ); document.write( "y = 1.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this value of y to find x \n" ); document.write( "x = 20*y \n" ); document.write( "x = 20*1.6 ... replace y with 1.6 \n" ); document.write( "x = 32\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The father is currently 32 years old \n" ); document.write( " |