document.write( "Question 996938: Perform each indicated operation and simplify the result\r
\n" ); document.write( "\n" ); document.write( "cot ϑ + 1/cot ϑ\r
\n" ); document.write( "\n" ); document.write( "Answer: csc ϑ sec ϑ or 1/sin ϑ cos ϑ\r
\n" ); document.write( "\n" ); document.write( "how do u find those answers?
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Algebra.Com's Answer #615205 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"cot%28theta%29\" + \"1%2Fcot%28theta%29\" = \"%28cos%28theta%29%29%2Fsin%28theta%29\" + \"1%2F%28%28cos%28theta%29%29%2F%28sin%28theta%29%29%29\" = \"%28cos%28theta%29%29%2Fsin%28theta%29\" + \"%28sin%28theta%29%29%2F%28cos%28theta%29%29\" =     (write it with the common denominator which is \"sin%28theta%29%2Acos%28theta%29\"\r
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\n" ); document.write( "\n" ); document.write( "= \"%28cos%5E2%28theta%29%29%2F%28sin%28theta%29%2Acos%28theta%29%29\" + \"%28sin%5E2%28theta%29%29%2F%28sin%28theta%29%2Acos%28theta%29%29\" = \"%28sin%5E2%28theta%29+%2B+cos%5E2%28theta%29%29%2F%28sin%28theta%29%2Acos%28theta%29%29\" =     (now recall that \"sin%5E2%28theta%29+%2B+cos%5E2%28theta%29\" = \"1\") \r
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\n" ); document.write( "\n" ); document.write( "= \"1%2F%28sin%28theta%29%2Acos%28theta%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "It is what has to be proved.\r
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