document.write( "Question 996887: Tennis balls are packaged in a cylindrical can, and since they're round, that leaves a lot of empty space in the can. How much space? The radius of a tennis ball is 3.3cml; the can has the same radius for a nice tight fit, and the height of the can is six times that radius, which is 19.8 cm. Find the volume of empty space in the can. \n" ); document.write( "

Algebra.Com's Answer #615200 by mananth(16946) $\"\"$ $\"About$

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ball is 6 times the radius =19.8cm
\n" ); document.write( " diameter 6.6 cm\r
\n" ); document.write( "\n" ); document.write( "so three balls can be fytted into the can\r
\n" ); document.write( "\n" ); document.write( "Empty space in the can = Volume of can - volume of 3 balls\r
\n" ); document.write( "\n" ); document.write( "Vol of can height = 19.8
\n" ); document.write( "radius = 3.3cm\r
\n" ); document.write( "\n" ); document.write( "v= pi r^2 h\r
\n" ); document.write( "\n" ); document.write( "V= 3.14 * 3.3^2 * 19.8 = 677.05 cm^3\r
\n" ); document.write( "\n" ); document.write( "Volume of spheres = 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( "= (4/3) * 3.14 * (3.3)^3 = 150.45 cm^3\r
\n" ); document.write( "\n" ); document.write( "Volume of 3 balls = 3* 150.45 = 451.36\r
\n" ); document.write( "\n" ); document.write( "difference of volumes = empty space \n" ); document.write( "

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