document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996899>Question 996899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a number is doubled and then added to 3, the new result is equal to 15 decreased by the original number. Find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615184 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52790)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "2x + 3 = 15 - x.\r<BR>\n" );
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document.write( "3x = 15 - 3,\r<BR>\n" );
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document.write( "3x = 12,\r<BR>\n" );
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document.write( "x = 4.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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