document.write( "Question 996893: solve for x: 0.008 -0.02x=0.03 Then evaluate : x^2+x+.89 \n" ); document.write( "
Algebra.Com's Answer #615174 by Boreal(15235) You can put this solution on YOUR website! 0.008 -0.02x=0.03 Then evaluate : x^2+x+.89 \n" ); document.write( "-0.02x=0.024 \n" ); document.write( "divide both sides by -0.02 \n" ); document.write( "x= -1.2 \n" ); document.write( "====== \n" ); document.write( "x^2+x+89, where x=-1.2 \n" ); document.write( "1.44-1.2+0.89=2.33-1.2=1.13 \n" ); document.write( " |