document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996845>Question 996845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that x is a binomial experiment with n = 15 and p = 0.3.<BR>\n" );
document.write( "Compute P(x = 2). Show your work. <BR>\n" );
document.write( "Use Excel to get the printout of the probability distribution. Use “=binom.dist” function. See page 66 of the course packet and pages 155-156 of your textbook. <BR>\n" );
document.write( "Use the binomial probability distribution from part c to calculate P(x &#8805; 8).<BR>\n" );
document.write( "Use the short-cut formula to compute E(x), and the variance and the standard deviation of x. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615133 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(x=2)=15C2(0.3)^2(0.7)^13=105*(0.09)(0.009688)<BR>\n" );
document.write( "without rounding until the end, that is 0.0916<BR>\n" );
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document.write( "P (x>=8)  Use the table.  The cumulative probability through x=7 is 0.95, so the probability of >=8 is 0.05.<BR>\n" );
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document.write( "E(x)=np=15*0.3=4.5<BR>\n" );
document.write( "variance is np(1-p)=15(0.3)(0.7)=3.15<BR>\n" );
document.write( "sd=1.77<BR>\n" );
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