document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996810>Question 996810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student scored 72 and 89 on her first two quizzes.  Write and solve a compound inequality to find the possible values for the third quiz score that would give her an average between 75 and 90, inclusive.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615101 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The setup for this problem is<BR>\n" );
document.write( "75 < (72+89+x)/3 < 90<BR>\n" );
document.write( "Now multiply everything by three and simplify and get<BR>\n" );
document.write( "225 < 161 + x < 270<BR>\n" );
document.write( "Now subtract 161 and get<BR>\n" );
document.write( "64 < x < 109 </SPAN>\n" );
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