document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996808>Question 996808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you work it out\r<BR>\n" );
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document.write( "(4/25)to the power of -3/2.   X.     (8/25) to the power of 1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615091 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4/25)^( -3/2)=<BR>\n" );
document.write( "(25/4)^(3/2).  Invert the fraction, change the sign of the exponent.<BR>\n" );
document.write( "=25^3/2 divided by 4^3/2<BR>\n" );
document.write( "The numerator is 125, square root (2) of 25 then cubed.<BR>\n" );
document.write( "The denominator is 8 by the same approach<BR>\n" );
document.write( "Answer is (125/8)<BR>\n" );
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document.write( "This is 8^1/3 divided by 125^1/3<BR>\n" );
document.write( "That is 2/5. </SPAN>\n" );
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