document.write( "Question 996757: Polluted water is passed through a series of filters. Each filter removes 59% of the remaining impurities. Initially the water contains impurities at a level of 400 parts per million (ppm). Determine a rule for the function g , that gives the remaining level of impurities, L , after the water has passed through a series of n filters.
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document.write( "G(n)=?????\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #615065 by Theo(13342)![]() ![]() You can put this solution on YOUR website! each filter removes 59% of the remaining impurities.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "remaining level of impurity equals 41% of the original impurity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "400 parts per million start with. \n" ); document.write( "pass through filter once. \n" ); document.write( "remove .59 * 400 = 235 \n" ); document.write( "remaining = .41 * 400 = 164 \n" ); document.write( "235 + 164 = 400.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can use .41 as the factor for the remaining impurities.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "400 * .41 = 164 * .41 = 67.24 * .41 = 27.5684\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "basically you have 400 * .41 * .41 * .41 which is the same as 400 * .41^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "400 * .41^3 = 27.5684.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this works for any number of times you pass though the filter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "g(n) = 400 * .41^n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when n = 3, g(3) = 400 * .41^3 = 27.5684.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could have used any variable name, such as x, as well.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "g(x) = 400 * .41^x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 3, g(3) = 400 * .41^3 = 27.5684.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |