document.write( "Question 996698: Goes through intercepts (5, 0) and (0-3) how to graph that? \n" ); document.write( "
Algebra.Com's Answer #615029 by Theo(13342)\"\" \"About 
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(x1,y1) = (5,0)
\n" ); document.write( "(x2,y2) = 0,-3)\r
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\n" ); document.write( "\n" ); document.write( "slope = (y2-y1) / (x2-x1) = (-3-0) / 0-5) = -3/-5 = 3/5\r
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\n" ); document.write( "\n" ); document.write( "y-intercept is equal to -3.\r
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\n" ); document.write( "\n" ); document.write( "the coordinate point of the y-intercept is taken from (0,-3) which tells you the value of y when the value of x is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "slope intercept form of the equation of a straight line is equal to y = mx + b.\r
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\n" ); document.write( "\n" ); document.write( "m is the slope
\n" ); document.write( "b is the y intercept.\r
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\n" ); document.write( "\n" ); document.write( "this becomes y = 3/5 * x - 3.\r
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\n" ); document.write( "\n" ); document.write( "that's the equation you want to graph.\r
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\n" ); document.write( "\n" ); document.write( "it looks like this:\r
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