document.write( "Question 996713: Normally it take 3 hours for a train ti run from A to B one day due to a minor trouble the train reduce the speed by 12 km/hr si it took 3/4th of an hours more than the usual.what is the distance fron A to B. \n" ); document.write( "

Algebra.Com's Answer #615028 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "             speed        time        distance\r\n" );
document.write( "NORMAL        r            3            d\r\n" );
document.write( "TROUBLE       r-12         3+3/4        d\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Normal situation gives $\"r=d%2F3\"$ .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"%28r-12%29%283%263%2F4%29=d\"$
\n" ); document.write( " $\"%28d%2F3-12%29%2815%2F4%29=d\"$
\n" ); document.write( " $\"12%28d%2F3-12%29%2815%2F4%29=12d\"$
\n" ); document.write( " $\"3%28%28d%2F3%29-12%29%2A4%2815%2F4%29=12d\"$ , split the factor 12 into the two smaller factors;
\n" ); document.write( " $\"%28d-36%29%2A15=12d\"$
\n" ); document.write( " $\"15d-36%2A15=12d\"$
\n" ); document.write( " $\"3d-36%2A15=0\"$
\n" ); document.write( " $\"3d=3%2A12%2A15\"$
\n" ); document.write( " $\"d=12%2A15\"$
\n" ); document.write( " $\"highlight%28d=180%29\"$ \n" ); document.write( "

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