document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996685>Question 996685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2-x=2 how do I get rid of the negative that is going to be left in front of the x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615006 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That's easy. You should know that working with equations as long as you do to both sides the same you're OK. In the case of your problem:<BR>\n" );
document.write( "2-x=2 Add x to both sides<BR>\n" );
document.write( "2-x+x= 2+x on the left -x and +x cancel one another, so you get:<BR>\n" );
document.write( "2= 2+x To further simplify, subtract 2 from both sides:<BR>\n" );
document.write( "0= x or, just to write it more elegantly:<BR>\n" );
document.write( "x= 0 </SPAN>\n" );
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