document.write( "Question 996635: Find two consecutive integers that ten more than twice the smaller is seven less than three times the larger. \n" ); document.write( "

Algebra.Com's Answer #614995 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " let two consecutive integers be: $\"x\"$ and $\"x%2B1\"$
\n" ); document.write( " ten more than twice the smaller : $\"2x%2B10\"$
\n" ); document.write( "is :=
\n" ); document.write( "seven less than three times the larger: $\"3%28x%2B1%29-7\"$ \r
\n" ); document.write( "\n" ); document.write( "so, we have $\"2x%2B10=3%28x%2B1%29-7\"$ ........solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B10=3x%2B3-7\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B10=3x-4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4%2B10=3x-2x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=14\"$ => smaller number\r
\n" ); document.write( "\n" ); document.write( "then larger number is $\"x%2B1=15\"$ \r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B10=3%28x%2B1%29-7\"$
\n" ); document.write( " $\"2%2A14%2B10=3%2815%29-7\"$
\n" ); document.write( " $\"28%2B10=45-7\"$
\n" ); document.write( " $\"38=38\"$
\n" ); document.write( " \n" ); document.write( "

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