document.write( "Question 85250: Helllo,\r
\n" ); document.write( "\n" ); document.write( "I need help with this word problem:\r
\n" ); document.write( "\n" ); document.write( "Mrs. Lambert invested a portion of $15,000 at 10% annual interest and the balance at 6% annual interest. If her investments earned $1260 for the year, how much did she invest in each account?\r
\n" ); document.write( "\n" ); document.write( "Thank you!!
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Algebra.Com's Answer #61494 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
.10X+.06(15000-X)=1260
\n" ); document.write( ".10X+900-.06X=1260
\n" ); document.write( ".04X=1260-900
\n" ); document.write( ".04X=360
\n" ); document.write( "X=360/.04
\n" ); document.write( "X=9000 INVESTED @ 10%.
\n" ); document.write( "15000-9000=6000 INVESTED @ 6%.
\n" ); document.write( "PROOF
\n" ); document.write( ".10*9000+.06*6000=1260
\n" ); document.write( "900+360=1260
\n" ); document.write( "1260=1260
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