document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996513>Question 996513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two number is 21.five times the first is added to 2 times the second number is 66.find the two number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614935 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call them x and y.  Thus<BR>\n" );
document.write( "x + y = 21  and then<BR>\n" );
document.write( "5x + 2y = 66<BR>\n" );
document.write( "Multiply the top equation by two and subtract from the bottom one...<BR>\n" );
document.write( "5x + 2y = 66<BR>\n" );
document.write( "-(2x + 2y = 42)<BR>\n" );
document.write( "and we get<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "y = 21-x = 13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );