document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996497>Question 996497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a radiator contains 16 quarts of fluid that is 15% antifreeze. in order to prepare for the winter joe wants the fluid to be 60% antifreeze. he has a supply of 75% antifreeze solution. how many quarts should he drain and replace with his 75% antifreeze to get his desired mixture </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614917 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .75*16+.15x-(.75*16)=.60<BR>\n" );
document.write( "12+.15x-12= .6<BR>\n" );
document.write( "x= 4<BR>\n" );
document.write( "He needs 4 quarts at .15 and 12 quarts at .75 to obtain a .60 (60%) mix.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "4/16= .25 25% of the 16 quarts will be at a concentration of 15%<BR>\n" );
document.write( "12/16= .75 75% of the 16 quarts will be at a concentration of 75%<BR>\n" );
document.write( ".25*.15= .0375<BR>\n" );
document.write( ".75*.75= .5625<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "Total......0.6 or 60% We have the correct answer </SPAN>\n" );
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