document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996489>Question 996489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 11 more than another number. find the two numbers if three times the larger number exceed four times the smaller number by 4?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614914 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call one number x and another number y.<BR>\n" );
document.write( "one number is 11 more than another number:<BR>\n" );
document.write( "x = y+11 <---Value of x<BR>\n" );
document.write( "three times the larger number exceed four times the smaller number by 4?<BR>\n" );
document.write( "3x+4 = 4y Now, in this equation, let's replace x with the value of x:<BR>\n" );
document.write( "3(y+11)+4= 4y Multiply on left<BR>\n" );
document.write( "3y+33+4= 4y Add numbers on left and subtract 3y on both sides<BR>\n" );
document.write( "37= 1y  and we can write this simply as<BR>\n" );
document.write( "y= 37<BR>\n" );
document.write( "Proof<BR>\n" );
document.write( "One number is 11 more than another number, and since 37 is \"another number\", 37+11= \"one number\", 37+11= 48 Next, the problem says, three times the larger number exceed four times the smaller number by 4:<BR>\n" );
document.write( "4*37-3*48= 4 Multiply<BR>\n" );
document.write( "148-144= 4 We've got the right answer </SPAN>\n" );
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