document.write( "Question 996388: log2(5x(x-8))=log2A+log2x+log2f(x)\r
\n" ); document.write( "\n" ); document.write( "A=5\r
\n" ); document.write( "\n" ); document.write( "f(x)=? \n" ); document.write( "
Algebra.Com's Answer #614898 by Theo(13342)\"\" \"About 
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A = 5
\n" ); document.write( "log2(A) = log2(5)
\n" ); document.write( "log2(A) + log2(x) = log2(5) + log2(x) = log2(5x)
\n" ); document.write( "subtract log2(5x) from both sides of the equation to get:
\n" ); document.write( "log2(5x*(x-8)) - log2(5x) = log2(f(x))
\n" ); document.write( "this is equivalent to:
\n" ); document.write( "log2((5x*(x-8)/(5x)) = log2(f(x))
\n" ); document.write( "simplify to get log2(x-8) = log2(f(x))
\n" ); document.write( "this is true if and only if x-8 = f(x)
\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "you are using the properties of logarithms that state:\r
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\n" ); document.write( "\n" ); document.write( "log(a) + log(b) = log(a*b)\r
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\n" ); document.write( "\n" ); document.write( "log(a) - log(b) = log(a/b)\r
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