document.write( "Question 996381: If \"+f%28x%29+=+1+%2B+%281%2Fx%29+\", find f(f(f(1))).\r
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Algebra.Com's Answer #614862 by ikleyn(52778)\"\" \"About 
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\n" ); document.write( "If \"+f%28x%29+=+1+%2B+%281%2Fx%29+\", find f(f(f(1))).
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\n" ); document.write( "\n" ); document.write( "f(1) = 1 + \"1%2F1\" = 1 + 1 = 2.\r
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\n" ); document.write( "\n" ); document.write( "f(f(1)) =     ( substitute  2  as  f(1) )     = f(2) = 1 + \"1%2F2\" = \"1\"\"1%2F2\" = \"3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "f(f(f(1))) =     ( substitute  \"3%2F2\"  as  f(f(1)) )      = f(\"3%2F2\") = 1 + \"1%2F%28%283%2F2%29%29\" = 1 + \"2%2F3\" = \"1\"\"2%2F3\".\r
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