document.write( "Question 85295: Problem:
\n" ); document.write( "The length of a rectangular poool is 40 feet. the width is 24 feet. A walkway of uniform width surrounds the pool. The combined area of the pool and walkway is 2240 sqft. Find the width of the walkway?\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "
\n" ); document.write( " 40s+40s+24s+24s = 2240
\n" ); document.write( " 128s = 2240
\n" ); document.write( " s = 17.5\r
\n" ); document.write( "\n" ); document.write( " I dont know how to go about it... I know this is wrong!!!!
\n" ); document.write( " Plz help!!!! I do not have the ISBN because that is from one of my exams .
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Algebra.Com's Answer #61486 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
40*24=960 SQUARE FEET FOR THE POOL.
\n" ); document.write( "(40+2X)(24+2X)=2240 THESE ARE THE NEW DIMENTIONS WHEN YOU ADD THE WALKWAY WITH A WIDTH OF X. tHE BEST WAY TO VISUALIZE THIS IS TO DRAW A DIAGRAM OF THE POOL AND ADD THE WALKWAY OF WIDTH X.
\n" ); document.write( "960+48X+80X+4X^2=2240
\n" ); document.write( "4X^2+128X+960-2240=0
\n" ); document.write( "4X^2+128X-1280=0
\n" ); document.write( "4(X^2+32X-320)=0
\n" ); document.write( "4(X-8)(X+40)=0
\n" ); document.write( "X-8=0
\n" ); document.write( "X=8 FEET ANSWER FOR THE WIDTH OF THE WALKWAY.
\n" ); document.write( "PROOF
\n" ); document.write( "(40+2*8)(24+2*8)=2240
\n" ); document.write( "(40+16)(24+16)=2240
\n" ); document.write( "56*40=2240
\n" ); document.write( "2240=2240\r
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