document.write( "Question 996373: Bill left school and drove toward the train station. One hour later Jessica left driving at 80 km/h in an effort to catch up to Bill. After driving for 3 hours Jessica finally caught up. Find bills average speed \n" ); document.write( "

Algebra.Com's Answer #614843 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
Common form of travel rates exercise.\r
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\n" ); document.write( "\n" ); document.write( "Most directly related. http://www.algebra.com/my/Uniform-Rates-Travel%3A-same-direction-but-different-travel-times-meet-when%3F.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "http://www.algebra.com/my/Uniform-Rates-Travel%3A-Two-Speeds-Differ-by-Constant-Same-Distance.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "Analyzing your example, Jessica traveled 3 hours, and if she left 1 hour AFTER Bill, then Bill traveled 3+1 hours. We can make this data table:
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document.write( "         speed    time     distance\r\n" );
document.write( "BILL       r       3+1      d\r\n" );
document.write( "JESSICA    80      3        d\r\n" );
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\n" ); document.write( "\n" ); document.write( " $\"system%28r%2A4=d%2C80%2A3=d%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Simple substitution for d.
\n" ); document.write( " $\"r=d%2F4\"$
\n" ); document.write( " $\"r=%2880%2A3%29%2F4\"$
\n" ); document.write( " $\"highlight%28r=60%29\"$ \n" ); document.write( "

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