document.write( "Question 996312: You need a new cell phone for emergencies only company a charges $12 per month plus $0.10 per minute while Company B charges $0.15 per minute with no monthly service charge for how many minutes will the monthly cost to be the same \n" ); document.write( "
Algebra.Com's Answer #614810 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Let's call the minutes x: \n" ); document.write( "Company A: \n" ); document.write( "12+0.10x \n" ); document.write( "Company B: \n" ); document.write( "0.15x When will costs be the same? When A=B: \n" ); document.write( "12+0.10x=0.15x Now subtract 0.10x from both sides: \n" ); document.write( "12= 0.05x \n" ); document.write( "Divide both sides by 0.05: \n" ); document.write( "x=240 At 240 minutes both will cost you the same. \n" ); document.write( "-------------------------- \n" ); document.write( "Now, every minute OVER 240 will cost you 0.10 with A and 0.15 with B, therefore if you are going to use more than 240 minutes choose A. \n" ); document.write( "On the other hand, if you are going to use LESS than 240 minutes... what happens? Let's pretend you will use 200 minutes: \n" ); document.write( "A)12+0.10(200)= 32 \n" ); document.write( "B)0.15(200)= 30 \n" ); document.write( "So, as you can see, if you use less than 240 minutes B is cheaper. k ijeoi \n" ); document.write( " |