document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996263>Question 996263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is six times as old as her son. In 9 years she will be three times as old as her son.How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614786 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be her son's age now.  Let Mom's age be m now,<BR>\n" );
document.write( "so then we have<BR>\n" );
document.write( "m = 6x<BR>\n" );
document.write( "In 9 years,<BR>\n" );
document.write( "m + 9 = 3(x + 9)<BR>\n" );
document.write( "Substitute 6x in for m and get<BR>\n" );
document.write( "6x + 9 = 3x + 27<BR>\n" );
document.write( "3x = 18<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "m = 36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );