document.write( "Question 996272: 1.) The solution to sqrt 2x+3 - sqrt x-1=1 is x=3? true or false\r
\n" ); document.write( "\n" ); document.write( "2.) The solution to the radical function 1 = sqrt x-5 is x=6? true or false\r
\n" ); document.write( "\n" ); document.write( "3.) Solve: sqrt x = sqrt 2x-6\r
\n" ); document.write( "\n" ); document.write( "4.) Solve: 3 + sqrt x-3 = 6\r
\n" ); document.write( "\n" ); document.write( "5.) Solve: sqrt x-3 = sqrt 2 - sqrt x for x
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Algebra.Com's Answer #614780 by ikleyn(52800)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "1.) The solution to  \"sqrt%282x%2B3%29\" - \"sqrt%28x-1%29\" = \"1\" is x=3?  true or false?     Substitute  x=3  into this equation and check if the right side is equal to the left.  It is easy.\r
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\n" ); document.write( "\n" ); document.write( "2.) The solution to the radical function  \"1\" = \"sqrt%28x-5%29\"  is x=6?  true or false?     Substitute x=6 into equation and check.  It is easy.\r
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\n" ); document.write( "\n" ); document.write( "3.) Solve: \"sqrt%28x%29\" = \"sqrt%282x-6%29\".     Square both sides.  It is easy.\r
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\n" ); document.write( "\n" ); document.write( "4.) Solve: \"3\" + \"sqrt%28x-3%29\" = \"6\".     Move  3  to the right side with the opposite sign.  Calculate.  Then square both sides.\r
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\n" ); document.write( "\n" ); document.write( "5.) Solve: \"sqrt%28x-3%29\" = \"sqrt%282%29\" - \"sqrt%28x%29\" for x.     Not sure that I correctly put parentheses.  IT IS YOURS RESPONSIBILITY.\r
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