document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85291>Question 85291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The cost for a long-distance telephone call is $0.36 for the first minute and $0.4 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk with out exceeding $3.00 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61477 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The cost for a long-distance telephone call is $0.36 for the first minute and $0.40 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk with out exceeding $3.00<BR>\n" );
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document.write( "Let # of minutes of calling be \"x\".<BR>\n" );
document.write( "Cost(x) = 0.36 + (x-1)0.40\r<BR>\n" );
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document.write( "INEQUALITY:<BR>\n" );
document.write( "0.36 + (x-1)*0.40 <=3<BR>\n" );
document.write( "36 + 40(x-1) <= 300<BR>\n" );
document.write( "40x-4 <= 300<BR>\n" );
document.write( "40x <= 304<BR>\n" );
document.write( "x<=7.6 minutes <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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