document.write( "Question 996252: I am trying to solve this problem using the quadratic formula but I need help. here is the problem:
\n" ); document.write( "x^2+12=0
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Algebra.Com's Answer #614760 by LinnW(1048) $\"\"$ $\"About$

You can put this solution on YOUR website!
First the quadratic formula
\n" ); document.write( " $\"%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F2a\"$
\n" ); document.write( "Our equation is $\"x%5E2%2B12=0\"$
\n" ); document.write( "The a in the formula is the coefficient of the square term
\n" ); document.write( "so for our equation, a = 1
\n" ); document.write( "Since our equation does not have a middle term, b = 0
\n" ); document.write( "c is the value of the constant which for us is 12
\n" ); document.write( "Substituting we get
\n" ); document.write( " $\"%28-0+%2B-+sqrt%280-4%281%29%2812%29%29%29%2F2%281%29\"$
\n" ); document.write( " $\"%28-0+%2B-+sqrt%28-48%29%29%2F2\"$
\n" ); document.write( " $\"%28-0+%2B-+sqrt%28-12%2A4%29%29%2F2\"$
\n" ); document.write( " $\"%28-0+%2B-+2%2Asqrt%28-12%29%29%2F2\"$
\n" ); document.write( " $\"%28-0+%2B-+sqrt%28-12%29%29\"$
\n" ); document.write( " $\"%28%2B-+sqrt%28-12%29%29\"$
\n" ); document.write( "Since we have the square root of a negative number we have no real root
\n" ); document.write( "Notice that we could have solved more easily.
\n" ); document.write( "Take our equation, $\"x%5E2%2B12=0\"$
\n" ); document.write( "add -12 to each side
\n" ); document.write( " $\"x%5E2=-12\"$
\n" ); document.write( "Take the square root of each side and we get
\n" ); document.write( " $\"x=%2B-sqrt%28-12%29\"$ \n" ); document.write( "

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