document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=996113>Question 996113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If m<1 is twice the measure of its complement (<2), then determine the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614673 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = measure of angle 1<BR>\n" );
document.write( "y = measure of angle 2\r<BR>\n" );
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document.write( "\"m<1 is twice the measure of its complement (<2)\" so, \r<BR>\n" );
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document.write( "m < 1 = 2*( m < 2)<BR>\n" );
document.write( "x = 2*y\r<BR>\n" );
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document.write( "The two angles are complementary, so they add to 90 degrees\r<BR>\n" );
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document.write( "x+y = 90<BR>\n" );
document.write( "2y+y = 90 ... replaced x with 2y (see equation above)<BR>\n" );
document.write( "3y = 90<BR>\n" );
document.write( "3y/3 = 90/3<BR>\n" );
document.write( "y = 30\r<BR>\n" );
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document.write( "If y = 30, then x = 2*y = 2*30 = 60\r<BR>\n" );
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document.write( "The two angles are <font color=\"red\">30 and 60</font> </SPAN>\n" );
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