document.write( "Question 996096: Find the inverse of y=f(t)=sqrt(5t)+7\r
\n" ); document.write( "\n" ); document.write( "here are my calculation for this problem, and I would appreciate if you could point out if I did a mistake.\r
\n" ); document.write( "\n" ); document.write( "f(t)=sqrt(5t)+7
\n" ); document.write( "f(y)=sqrt(5x)+7\r
\n" ); document.write( "\n" ); document.write( "x=sqrt(5y)+7
\n" ); document.write( "x-7=sqrt(5y)
\n" ); document.write( "(x-7)^2=5y
\n" ); document.write( "(x-7^2/5)=y
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #614658 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The only error I see is in the last line. It should be y = ( (x-7)^2 )/5. All of (x-7)^2 is over the 5.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Keep in mind that because the range of sqrt(5t)+7 is [7,infinity), the domain of the inverse is going to be [7,infinity)
\n" ); document.write( "
\n" );