document.write( "Question 996042: Five years ago, Chuck was twice as old as Jeanne will be 6 years from now. He is now one year older than 4 times her age. How old was Chuck 5 years ago? How old will Jeanne be 6 years from now? \n" ); document.write( "
Algebra.Com's Answer #614628 by stanbon(75887)\"\" \"About 
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Five years ago, Chuck was twice as old as Jeanne will be 6 years from now. He is now one year older than 4 times her age. How old was Chuck 5 years ago? How old will Jeanne be 6 years from now?
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\n" ); document.write( "Equation(s):
\n" ); document.write( "c-5 = 2(j+6)
\n" ); document.write( "c = 4j+1
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\n" ); document.write( "Substitute for \"c\" and solve for \"j\"::
\n" ); document.write( "4j+1-5 = 2j+12
\n" ); document.write( "2j = 16
\n" ); document.write( "j = 8 (Jeanne's age now)
\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "c = 4j+1
\n" ); document.write( "c = 4*8+1 = 33 yrs (Chuck's age now)
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\n" ); document.write( "How old was Chuck 5 years ago?
\n" ); document.write( "Ans: 33-5 = 28 yrs
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\n" ); document.write( "How old will Jeanne be 6 years from now?
\n" ); document.write( "Ans: 8+6 = 14 yrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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