document.write( "Question 85275: factor by grouping
\n" ); document.write( "x^3-3x^2+4x-12
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Algebra.Com's Answer #61461 by Edwin McCravy(20056)\"\" \"About 
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\n" ); document.write( "factor by grouping
\n" ); document.write( "x³ - 3x² + 4x - 12\r
\n" ); document.write( "\n" ); document.write( "Factor x² out of the first two terms, and
\n" ); document.write( "factor 4 out of the last two terms:\r
\n" ); document.write( "\n" ); document.write( "x²(x - 3) + 4(x - 3)\r
\n" ); document.write( "\n" ); document.write( "Now there are only two terms and they have a
\n" ); document.write( "common factor or (x - 3). So we factor (x - 3)
\n" ); document.write( "out of each term.\r
\n" ); document.write( "\n" ); document.write( "(x - 3)(x² + 4)\r
\n" ); document.write( "\n" ); document.write( "It doesn't factor any further.\r
\n" ); document.write( "\n" ); document.write( "Edwin
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