document.write( "Question 995916: Help is urgently needed.\r
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document.write( "Find the remainder when x^100 + 2x^99 +3x^98 +... 100x is divided by \n" );
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Algebra.Com's Answer #614544 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! synthetic division \n" ); document.write( "1/1+2+3+4+5... \n" ); document.write( " =1+1 \n" ); document.write( "===3 +3 \n" ); document.write( "====== \n" ); document.write( "=====6 +4 \n" ); document.write( "The first four terms are \n" ); document.write( "x^99+3x^98+6x^97+10x^96+... \n" ); document.write( "The coefficient of each term is the sum of all the preceding terms plus the coefficient of the next term. \n" ); document.write( "The pattern will be 15,21,28,36.45.55..... \n" ); document.write( "The coefficient of the 100th term is the sum of the preceding 99 terms plus the coefficient of the 100th term (100), so the quotient will be dividing x-1 into 4950x+100x or 5050 x. \n" ); document.write( "That will go in 5050 times, and we subtract 5050x-5050, so that the remainder is 5050. \n" ); document.write( " \n" ); document.write( " |