document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995874>Question 995874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the concentration of a solution of acid that was made by adding 75mL of a 20% acid concentration to 50mL of a 40% acid concentration? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614522 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of mL of the first solution.<BR>\n" );
document.write( "y = number of mL of the second solution.\r<BR>\n" );
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document.write( ".2x = number of mL of acid in the first solution.<BR>\n" );
document.write( ".4y = number of mL of acid in the second solution.\r<BR>\n" );
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document.write( "the total mL in your final solution is x + y.\r<BR>\n" );
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document.write( "the total mL of acid in your final solution is .2x + .4y.\r<BR>\n" );
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document.write( "you know that x is equal to 75mL and you know that y is equal to 50mL.\r<BR>\n" );
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document.write( "you can replace x and y with those figures in your formulas as shown below:\r<BR>\n" );
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document.write( "x + y becomes 75 + 50 which becomes 125mL.\r<BR>\n" );
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document.write( ".2x + .4y becomes .2*75 + .4*50 which becomes 15 + 20 which becomes 35mL.\r<BR>\n" );
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document.write( "you have 35mL of acid in your final solution out of a total of 125mL in your final solution.\r<BR>\n" );
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document.write( "the percentage of acid is therefore equal to 35/125 = 7/25 = .28 * 100 = 28%.\r<BR>\n" );
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