document.write( "Question 995852: the probability that the operations being successful is 3/4 . what is the probability of winning 3 consecutive operations? \n" ); document.write( "
Algebra.Com's Answer #614521 by Theo(13342)\"\" \"About 
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p(success) = 3/4\r
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\n" ); document.write( "\n" ); document.write( "p(success three times in a row) = 3/4 * 3/4 * 3/4 = 27/64\r
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\n" ); document.write( "\n" ); document.write( "the probability of 3 successes 1 time in a row is 3/4.
\n" ); document.write( "the probability of 3 successes 2 times in a row is 3/4 * 3/4.
\n" ); document.write( "the probability of 3 successes 3 times in a row is 3/4 * 3/4 * 3/4.\r
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