document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995848>Question 995848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Cardenas has $8.70 in his pocket. it is all change but only quarters and dimes. there are a total of 48 coins. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614512 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> q+d= 48 is the total of coins he has, so we can say that:<BR>\n" );
document.write( "q= 48-d - - Substitute value<BR>\n" );
document.write( "0.25q+0.10d= 8.70 Let's use the substitute value:<BR>\n" );
document.write( "0.25(48-d)+0.10d= 8.7 Multiply on left<BR>\n" );
document.write( "12-0.25d+0.10d= 8.7 Now add d on left and subtract 12 on both sides<BR>\n" );
document.write( "-0.15d= -3.30 Now divide both sides by -15, and remember that - divided by -= +<BR>\n" );
document.write( "d= 22 And:<BR>\n" );
document.write( "q= 48-22= 26<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "22*0.10= 2.20<BR>\n" );
document.write( "26*0.25= 6.50<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Total.....8.70 we have the correct answer <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );