document.write( "Question 995840: Explain why x^2+bx-c=0 must have one positive real and one negative real solution when b and c are real numbers and c>0 .\r
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document.write( "For what values of b will x^2+bx+1=0have real solutions? Clearly explain the reasoning you followed to reach your conclusion \n" );
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Algebra.Com's Answer #614506 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The first part is wrong. That cannot be justified. An example was already given a few minutes ago.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the discriminant for the second question. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |