document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995834>Question 995834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two thirds Kay's age increases by 12 is equal to twice her age decreased by 3. How old is Kay? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614490 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two thirds Kay's age increased by 12 is equal to twice her age decreased by 3. How old is Kay?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(2/3)(k + 12) = 2(k-3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(2/3)k + 8 = 2k-6<BR>\n" );
document.write( "(4/3)k = 14<BR>\n" );
document.write( "k = (3/4)14<BR>\n" );
document.write( "k = 42/4<BR>\n" );
document.write( "k = 10 1/2 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );