document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995832>Question 995832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 20% dye solution is to be mixed with 60% dye solution to get 240L of a 50% solution. how many liters of the 20% and 60% will be needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614482 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 20% dye solution is to be mixed with 60% dye solution to get 240L of a 50% solution. how many liters of the 20% and 60% will be needed? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
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document.write( "0.20x + 0.60(240-x) = 0.50*240<BR>\n" );
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document.write( "20x + 60*240 - 60x = 50*240<BR>\n" );
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document.write( "-40x = -10*240<BR>\n" );
document.write( "x = 240/4 = 60 L (amt. of 20% solution needed)<BR>\n" );
document.write( "240-x = 180 L (amt. of 60% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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