document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995825>Question 995825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the value of k so that 3x-2 is a factor of 6x^3 + 5x^2 + kx + 10. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614480 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine the value of k so that 3x-2 is a factor of 6x^3 + 5x^2 + kx + 10. <BR>\n" );
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document.write( "3x-2 is a factor if x = 2/3 is a zero.<BR>\n" );
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document.write( "Solve for \"k\"::<BR>\n" );
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document.write( "6(2/3)^3 + 5(2/3)^2 + (2/3)k + 10 = 0<BR>\n" );
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document.write( "6(8/27) + 5(4/9) + (2/3)k + 10 = 0<BR>\n" );
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document.write( "Multiply thru by 27 to get:<BR>\n" );
document.write( "48 + 60 + 36k + 270 = 0<BR>\n" );
document.write( "36k = -378<BR>\n" );
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document.write( "k = -10.5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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