document.write( "Question 995830: When the drain is opened on a swimming pool it takes the pool 6 hours to drain. When a small pump is used, it is able to drain in 5 hours. How many small pumps must be used to drain the pool in 2 hours?\r
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document.write( "What I have so far,
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document.write( "Let x = number of small pumps
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document.write( "(1/6) + x(1/5) = 1/2
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document.write( "But I get x = 5/3\r
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document.write( "So, am I to conclude that I need 2 pumps and they will drain the pool in under 2 hours? \n" );
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Algebra.Com's Answer #614476 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! When the drain is opened on a swimming pool it takes the pool 6 hours to drain. When a small pump is used, it is able to drain in 5 hours. How many small pumps must be used to drain the pool in 2 hours? \n" ); document.write( "------ \n" ); document.write( "Small pump DATA: \n" ); document.write( "rate = 1/5 job/hr \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "time * work rate per unit * # of units = work done \n" ); document.write( "------------------------- \n" ); document.write( "2(1/5)x = 1 job \n" ); document.write( "--- \n" ); document.write( "(2/5)x = 1 \n" ); document.write( "x = (5/2) # of small pumps needed \n" ); document.write( "------------ \n" ); document.write( "------------------- \n" ); document.write( "If you include the work done by the drain without the pumps you get: \n" ); document.write( "2((1/6)+(1/5)x) = 1 job \n" ); document.write( "[(1/3)]+(2/5)x] = 1 \n" ); document.write( "(2/5)X = 2/3 \n" ); document.write( "(X/5) = 1/3 \n" ); document.write( "x = 5/3 small pumps \n" ); document.write( "========\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |