document.write( "Question 995830: When the drain is opened on a swimming pool it takes the pool 6 hours to drain. When a small pump is used, it is able to drain in 5 hours. How many small pumps must be used to drain the pool in 2 hours?\r
\n" ); document.write( "\n" ); document.write( "What I have so far,
\n" ); document.write( "Let x = number of small pumps
\n" ); document.write( "(1/6) + x(1/5) = 1/2
\n" ); document.write( "But I get x = 5/3\r
\n" ); document.write( "\n" ); document.write( "So, am I to conclude that I need 2 pumps and they will drain the pool in under 2 hours?
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Algebra.Com's Answer #614476 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
When the drain is opened on a swimming pool it takes the pool 6 hours to drain. When a small pump is used, it is able to drain in 5 hours. How many small pumps must be used to drain the pool in 2 hours?
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\n" ); document.write( "Small pump DATA:
\n" ); document.write( "rate = 1/5 job/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "time * work rate per unit * # of units = work done
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\n" ); document.write( "2(1/5)x = 1 job
\n" ); document.write( "---
\n" ); document.write( "(2/5)x = 1
\n" ); document.write( "x = (5/2) # of small pumps needed
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\n" ); document.write( "If you include the work done by the drain without the pumps you get:
\n" ); document.write( "2((1/6)+(1/5)x) = 1 job
\n" ); document.write( "[(1/3)]+(2/5)x] = 1
\n" ); document.write( "(2/5)X = 2/3
\n" ); document.write( "(X/5) = 1/3
\n" ); document.write( "x = 5/3 small pumps
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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