document.write( "Question 995710: a chemist, mixed 40 ml of 8% acid with 60 ml of 12% acid solution. she used a portion of this solution and replaced it with distilled water. If the new solution tested 5.2% acid, how much of the original mixture did she use? \n" ); document.write( "

Algebra.Com's Answer #614439 by josgarithmetic(39618) $\"\"$ $\"About$

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First mixture:
\n" ); document.write( " $\"%2840%2A8%2B60%2A12%29%2F100=10.4%2Apercent\"$ , and this is 100 milliliters of solution.\r
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\n" ); document.write( "\n" ); document.write( "The Next mixture:
\n" ); document.write( "v volume was removed and replaced with distilled water, and this now became 5.2% acid. Find v.
\n" ); document.write( " $\"%28100%2A0.104-0.104v%29%2F100=0.052\"$ ;
\n" ); document.write( "Volume of starting solution stays the same 100 milliliters; just the concentration changes; this equation is setup in decimal fractions instead of percents. Solve for v. \n" ); document.write( "

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