document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995715>Question 995715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 consecutive multiples of is 333. Find the multiples<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614389 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 consecutive multiples of is 333. Find the multiples<BR>\n" );
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document.write( "1st: 3x<BR>\n" );
document.write( "2nd: 3(x+1)<BR>\n" );
document.write( "3rd: 3(x+2)<BR>\n" );
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document.write( "3(x+x+1+x+2) = 333<BR>\n" );
document.write( "3x+3 = 111<BR>\n" );
document.write( "3x = 108<BR>\n" );
document.write( "x = 36<BR>\n" );
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document.write( "3x = 108<BR>\n" );
document.write( "3(x+1) = 111<BR>\n" );
document.write( "3(x+2) = 114<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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